September 22, 2006

Quick question to mathematicians in the audience

A body is in freefall. Assuming normal gravity, how much distance will the body drop after, say, twenty seconds? Thirty seconds? I know the basic formula is 32 feet per second/per second, but math was never my strong suit, plus there's probably other aspects of physics I'm overlooking.

Or, put another way, a body dropped from about a thousand feet high: How long until it hits the ground?

PAD

Posted by Peter David at September 22, 2006 03:47 PM | TrackBack | Other blogs commenting
Comments
Posted by: David Hunt at September 22, 2006 03:56 PM

I don't have the ability to look it up myself at the moment, so I'll give a quick remimder to whatever math genius picks this up. Remember that, on Earth, a falling man will reach terminal velocity pretty quickly. I've got RPG sources that say terminal velocity will be reached by a falling man after about 5 seconds, but those aren't very stellar sources.

I now turn you over to the physics geek that will certainly answer this before I can look it up tommorrow.

Posted by: Den at September 22, 2006 03:58 PM

If we set the starting height at x=0 and the initial velocity = o, then the formula is x=-1/2gt^2 where g = 32 ft/s^2. So, at t=20 sec, x = 6400 feet downward. At t=30 sec, x = 14,400 feet.

Solving for t, we get t = sqrt(-2x/g). So, if the top is x=0 and the bottom is x=-1000, we get t= 7.9. So, it would take about 8 seconds to hit the bottom after being dropped from a height of 1000 feet.

That's my back of the envelop calculation. Hopefully, someone can double check my calculations.

Posted by: Luigi Novi at September 22, 2006 04:12 PM

Peter, is this for a story, or are you just bored right now? :-)

Posted by: David Hunt at September 22, 2006 04:23 PM

Just did some research on terminal velocity.

Den, those figures are correct in a vacuum with no atmosphere to create drag. A parachutist with his arms & legs spread will top out his falling velocity at 55 meters/second (c125 mph). Such a person would take about 8.34 seconds to fall 1000 feet with an initial velocity of 0.

I didn't find figures for someone flailing about in a panic, but I going with the unscientific assumption of a max velocity of 60 m/s. This takes the time down by only .02 seconds.

I made an simplifying assumption that the victim of this little though experiment would accelerate at a full 9.8 m/s/s (32 ft/s/s) until they hit terminal velocity. The fact that their acceleration would decrease as they approach terminal velocity is more than I can remember from a single college physics course, twenty years ago.

However, net answer is a bit over eight seconds to fall 1000 feet.

Posted by: Mike at September 22, 2006 04:27 PM

I did the slow subtraction from 1000 (-32, -64, -96, etc): About 8 seconds, which according to wikipedia, will reach 90% of terminal velocity.

Posted by: Douglas at September 22, 2006 04:29 PM

Den seem to be on the money - though here is a less complicated way of looking at it.

The falling body is movig at 32 feet per second in the 1st second, 64 in 2nd, 96 in 3rd, 128 in 4th, 160 in 5th, 192 in 6th, 224 in 7th & 256 in 8th.

32 + 64 + 96 + 128 + 160 + 192 + 224 + 256 = 1152 feet at the 8th second. so it is slightly less than 8 seconds.

Posted by: Sandahl at September 22, 2006 04:30 PM

It also depends on how fast one is falling. Someone wearing a parachute will fall slower than someone who isn't. Then there is the question on how long it takes to reach terminal velocity.

Den, your formula confuses me. Could you put in a key so that we know what everything is? Height was labeled x, but velocity wasn't labeled, and I'm having trouble with what g is. T is obviously time, so that's ok. Is g supposed to be velocity?

Thanks

Posted by: Den at September 22, 2006 04:34 PM

David, you are correct that my equations ignore atmospheric drag. Of course, Peter didn't give us any details about the nature of falling body, whether it was even a human being or just a bowling ball, so I just took the simplest assumptions and ignored atmospheric drag.

Since your example of someone spreading their arms and legs out added only about 1/3 of a second to the drop time, it's not really that huge of a simplification.

I'm assuming that Peter wants this for a story, so "about 8 seconds" is probably a good ballpark number of his purposes. So, unless he's actually got some resert project this weekend* where he needs a more precise drop time down to a fraction of a second, that's what we call good enough for government work.

*Then again, maybe he is working on something. Did you meet up with the Mythbusters gusy at Dragon Con, PAD? If you did, tell them I loved the episode where they tried to slow Buster's fall using a piece of plywood.

Posted by: Den at September 22, 2006 04:40 PM

x=height
t=time
g=acceleration of gravity
v=velocity*

*Since I assumed an initial velocity of zero, velocity drops out of the equation: x = -(1/2)gt^2 + v0t + x0

Where v0 is the initial velocity and x0 is the starting point.

BTw, the formula for velocity is just the derivative of the above equation:

v = -gt + v0.

Assuming again, no initial velocity, the velocity when our theoretical body goes splat would be approximately 256 ft/s. This again neglects air resistance.

Posted by: Sandahl at September 22, 2006 04:48 PM

Thanks, this makes much more sense.

Now to throw another variable into the mix. I wonder if weight would be a factor. If I remember correctly, it shouldn't since all objects will fall at the same rate. My question I guess would be, will they make contact with the ground at the same time?(Cats not counting since they seem to defy the laws of physics most of the time)

Posted by: Mike at September 22, 2006 04:55 PM

Sandahl, you answered your own question. Aristotle was cited saying that the heavier object would fall faster, but Galileo's demonstration was cited establishing the two objects would land at the same time.

Posted by: Sandahl at September 22, 2006 05:01 PM

Sorry for rambling then.

Posted by: David Hunt at September 22, 2006 05:06 PM

Den,

I agree that "around eight seconds" is probably good enough for whatever Mr. David is working on, but having put the work in, I decided that I'd post my answers, anyway. Didn't want to feel like it had all gone to waste.

Posted by: R.J. Carter at September 22, 2006 05:33 PM

Eight seconds to fall from 1000 feet.

Makes them cowboys who take that long to fall from a bull seem like wusses. :)

Posted by: Brian Edwards at September 22, 2006 06:30 PM

I've always wondered about that though - objects falling at the same rate. Wouldn't a heavier object have to fall faster? If acceleration [falling] is proportional to force, and gravitational force is a function of the two masses and the distances between them, then a heavier object should appear to fall faster [technically, the extra acceleration would be from the Earth’s movement, but that would be a matter of perspective]. Of course, this would only be noticeable if you were dropping something as massive as the moon. An object, around half of Earth’s mass should fall [assuming about 6400km between their centers of mass] around 12 or 13 m/s/s – If I did my calculations right.

Posted by: Scavenger at September 22, 2006 06:53 PM

So the arguments with Byrne have lead to this, have they?


:)

Posted by: Phillip at September 22, 2006 07:09 PM

In a vacuum, objects fall at the same rate. It's wind resistance that'll slow the velocity. Which is why there's that video of a feather and a bowling ball landing at the same time when dropped inside a vacuum.

Posted by: Jon Meltzer at September 22, 2006 07:41 PM

Laden or unladen?

Posted by: Sean Scullion at September 22, 2006 09:32 PM

African or European?

Posted by: John C. Kirk at September 23, 2006 05:54 AM

I think other people have covered the "how long to fall 1000 feet?" question (assuming that the person starts out "at rest"), so I'll just elaborate on a couple of other points.

sandahl - to give a more general version of den's formula, the relevant equation is "x = ut + 1/2 at^2".
x = distance travelled (in metres).
u = initial velocity (in metres/second).
t = time taken (in seconds).
a = acceleration (in metres/second/second).

You can use this to work out things like "if a car goes from 0-60 in 2 seconds, how far has it travelled in that time?" For falling, you just say that a=g, i.e. acceleration = gravity = 9.8m/s/s.

Scavenger - it's funny you should mention Byrne, since I picked up his FF Visionaries v6 TPB yesterday. This included a scene where the Beyonder jumps out of a window and Luke Cage jumps out after him. Quoth Luke: "I'm heavier'n him, so I should fall faster! Once I catch him maybe I can break his fall somehow!" Mind you, it didn't work, so this may have been a deliberate error for the character rather than the writer, since Cage also got confused about the gold standard, and had to be corrected by Iron Fist. (Also in fairness, that was from Secret Wars II #2, written by Shooter rather than Byrne himself.)

Coming back to PAD's original question (distance travelled in 20 or 30 seconds), if we again assume that the body starts at rest, and also ignore terminal velocity, then:
When t=20, x = 1960m = 6430ft = 1.2 miles.
When t=30, x = 4410m = 14468ft = 2.7 miles.

Terminal velocity is a bit beyond what I covered in my maths/physics education. I'll assume that the person has been tied up (and is unconscious), so we can take the maximum speed from the Wikipedia page that Mike linked to above, i.e. 320km/hour = 88.9 m/s (let's round down to 88.8 for the "Back to the Future" reference). This raises the question of "how long will it take to reach terminal velocity?" I.e. will the person actually be accelerating for 20/30 seconds, or would they be accelerating for 5 seconds and then travelling at a constant velocity after that?

88.8/9.8 = 9.06 seconds. (This confirms that terminal velocity can be ignored for the 8 second fall that people discussed above.) For simplicity, let's call this 9 seconds. In those 9 seconds, x = 0.5 * 9.8 * 9^2 = 396.9m.

When t=20, that gives 11 seconds of travel at 88.8m/s. This comes back to basic maths ("speed = distance/time"), i.e. x = 88.8*11 = 976.8m.

Similarly, when t=30, we have 21 seconds of travel at a constant velocity, so x = 88.8*21 = 1864.8m.

Combining the two parts:

After 20 seconds, the body would drop 1374m = 4507ft = 0.9 miles.

After 30 seconds, the body would drop 2262m = 7420ft = 1.4 miles.

Based on the phrase "the mile high club", I guess that's a plausible height for planes to be flying at.

Posted by: Brian Douglas at September 24, 2006 02:10 AM

The basic formula for distance, starting from rest, is d = 16 * t * t, where t is in seconds and d is in feet.

However, do to drag from air (I'm assuming he's falling in normal earth atmosphere), a human skydiver reaches a terminal velocity of 176 ft/s in 5.5 seconds. Thus, the formula would be

d = 484 + 176 * (t - 5.5)

So in 20 seconds, a body would fall 3036 feet. In 20 secods, a body would fall 4796 feet.

A body would fall 1000 feet in about 8.5 seconds.

Posted by: Brian Douglas at September 24, 2006 02:11 AM

The basic formula for distance, starting from rest, is d = 16 * t * t, where t is in seconds and d is in feet.

However, do to drag from air (I'm assuming he's falling in normal earth atmosphere), a human skydiver reaches a terminal velocity of 176 ft/s in 5.5 seconds. Thus, the formula would be

d = 484 + 176 * (t - 5.5)

So in 20 seconds, a body would fall 3036 feet. In 20 secods, a body would fall 4796 feet.

A body would fall 1000 feet in about 8.5 seconds.

Posted by: Tim Lynch at September 24, 2006 10:44 AM

I couldn't get to the site for a while (anybody else seeing this problem, too?), but now I figured I'd weigh in on a few things. The numbers (roughly 8 seconds, with or without air resistance) all look fine.

First... one comment.

Den seem to be on the money - though here is a less complicated way of looking at it.

The falling body is movig at 32 feet per second in the 1st second, 64 in 2nd, 96 in 3rd, 128 in 4th, 160 in 5th, 192 in 6th, 224 in 7th & 256 in 8th.

That's not entirely correct. The falling body is moving at 32 feet per second AT THE END OF the first second. During the first second, it's sped up from zero to 32 ft/s. Similarly, during the 2nd second, it speeds up from 32 to 64 ft/s. Therefore, if you want to do the adding up of distances you were trying you'd have to use average values: 16 feet in the first second (average of 0 and 32), 48 in the second, etc. You get an answer that's close to yours, but not quite.

I've always wondered about that though - objects falling at the same rate. Wouldn't a heavier object have to fall faster? If acceleration [falling] is proportional to force

It's proportional to force, yes, but it's also inversely proportional to the mass of the object being pulled. (Consider throwing a lasso around and pulling on a roller-skating gerbil vs. a truck.) Since the object's mass is both directly AND inversely proportional to the acceleration, then, it cancels out and the acceleration is mass-independent.

(If you bring in air resistance, the force of which doesn't depend on mass, then mass becomes a factor.)

Now I just want to know why Peter needs to know this! :-)

TWL

Posted by: Varjak at September 24, 2006 11:15 AM

I seemed to tremember that a good ballpark estimate for terminal velocity is 120 MPH in a prone position and 180 MPH in an upright position, because the same mass with less wind resistance will fall faster. But, for questionsa like this, why not check wikipedia?

http://en.wikipedia.org/wiki/Free_fall

This provides the equations for free fall, and includes a link to

http://bpesoft.com/s/wleizero/xhac/

which can be used to plug in your own numbers in a real-world situation including air resistance, etc. Using the skydiver free fall, from 1000 feet to sea level gives a fall time of 9.271 seconds and an impact velocity of 50.18 m/s (152.95 MPH).

Peter, this thread has provided you with more information than you ever wanted to know about free fall, hasn't it?

Posted by: Ray at September 24, 2006 12:20 PM

I don't need math. I just jumped out of an airplane at 1000 feet w/ a stop watch. It took me about 7.5 seconds to hit the ground, because I'm fast. I landed in some tall grass, so I'm fine. I hope this helps.

Posted by: The StarWolf at September 24, 2006 12:27 PM

Mass does factor into it because it isn't falling through a vacuum - assuming this takes places on Earth - and if a hot air updraft can keep a glider aloft for hours, it ought to measurably affect a falling body, depending on its mass. Enough to make a difference in the story? That's another matter.

Posted by: Alan Coil at September 24, 2006 12:59 PM

QUICK! SOMEBODY CALL A PHYSICS INSTRUCTOR!

It's been long decades since I had physics class, but I seem to remember that, because of resistance, a falling human body tops out somewhere around 100 feet per second. But I can't remember for sure.

I also seem to remember 16' 1st second, 32' 2nd second, 64' 3rd second, around 100' 4th second, 100' the 5th second, etc. That would seem to me to add up to around 12 seconds.

Falling 1000' while conscious would probably subject the person to time distortion, meaning it would seem all too short, yet an eternity.

Being nekkid might speed the fall slightly because of less drag.

For extra credit, who would fall faster? Calista Flockheart or Dolly Parton?

:)

Posted by: David Van Domelen at September 24, 2006 01:00 PM

The formula for terminal velocity involves density (about 1 for most people, but less if you have baggy clothing) and cross-sectional area (lower if you spread-eagle, higher if you arrow down) and the viscosity of the air, among other things. 120mph or 60m/s are cited as generic "most of the time it's around this" levels, since most people don't want ot mess about with differential equations.

Suffice to say, after about 200-220 meters, someone who isn't TRYING to fall really fast will hit terminal velocity. Someone who IS trying to fall fast, by diving, probably won't hit terminal velocity before hitting the ground if they start 300 meters (1000 feet) up. Numbers for each case already exist in this thread. :)

(For some reason, I got a blank page for here all yesterday, or I would have responded sooner.)

Posted by: Alan Coil at September 24, 2006 01:03 PM

After reading David Van Domelen's post, I wonder why the rest of the world hasn't switched over to feet instead of that hard-to-covert-to-feet meters crap.

;)

Posted by: Tim Lynch at September 24, 2006 02:14 PM

QUICK! SOMEBODY CALL A PHYSICS INSTRUCTOR!

You've got at least two in this thread already -- me, and David Van Domelen. (Den teaches in the sciences as well, though not physics specifically if I remember right.) How many more do you want? :-)

And while I agree with Dave's "most of the time it's around this" numbers, I tend to give a couple of others to my classes when this comes up. If you're falling spread out like a flying squirrel and have lots of baggy clothing, then it's probably more like 70-80 mph (less if you have a parachute, obviously). If you're wearing Spandex and deliberately falling like a dart, then it's significantly higher than 120 mph -- it'll depend on your weight, but it's a lot closer to 200 than it is to 120. Impact at the first speed (70-80 mph) is survivable with good ground conditions and significant good luck. Impact at the second speed typically requires that friends arrive with mops and squeegees. :-)

TWL

Posted by: Sean Scullion at September 24, 2006 10:02 PM

Okay, all you physics guys out there--would the horizontal velocity change the vertical velocity any? IE, jumping from a speeding plane rather than from a balloon or a cliff? I've halfway convinced myself that all it would do would be to change the location of contact with the surface, but there's something tickling me in the back of my head, and I just really hope it isn't a flea.

Tim, when you give that problem to your class, do you add that being spread out like a flying squirrel may lead to later problems with two Russian agents and a silly moose?

How baggy do your clothes have to be to add a significant difference in the time of the drop? (I swear the first one to mention parachute pants gets sixty lashes with a wet noodle.) Wouldn't moving through the air just push baggy clothes up against you, conforming to your shape, and making them come to a point over you? In my head, I've compared this to swimming in baggy clothes versus a wetsuit, since contrary to my wife's wishes, we've never skydived but I've been snorkeling since I was 11. Is this a valid comparison or am I completely off on this?

Hmmm. Stace wants me to jump out of a plane. Should I worry?

Posted by: Nick Eden at September 24, 2006 10:09 PM

I didn't find figures for someone flailing about in a panic, but I going with the unscientific assumption of a max velocity of 60 m/s. This takes the time down by only .02 seconds.

When I did my one and only jump the instructor told me that a controlled power dive - arms tucked in tight to the body and legs together - would result in falling at a terminal velocity of about 200mph. The flailing panic fall will certainly be slower.

Posted by: blacklantern at September 24, 2006 10:28 PM

I have a question, is it possible to break terminal velocity, if a person adds some type of thrust to their fall, like Superman flying after Lois after she's been thrown out a window, again.

Posted by: mike weber at September 25, 2006 06:08 AM

Posted by Sean Scullion at September 24, 2006 Posted by Sean Scullion

Okay, all you physics guys out there--would the horizontal velocity change the vertical velocity any? IE, jumping from a speeding plane rather than from a balloon or a cliff? I've halfway convinced myself that all it would do would be to change the location of contact with the surface, but there's something tickling me in the back of my head, and I just really hope it isn't a flea.

Not in general, unless it's a Very High horizontal velocity that carries you significantly over the curve of the Earth -up to the point where you hit orbital valocity and really are doing what Douglas Adams describes as "the way to fly" - hurling yourself at the ground and missing.

As to terminal velocity - are we calculating the time to reach V-sub-t simply as "so many seconds at 32 ft/sec/sec", or allowing for the reduced acceleration due to air drag?

Oh, since someone mentioned the gold standard upthread, and we're discussing if heavier masses fall faster or not - whichg weighs more - a pound of gold or a pound of feathers?

Posted by: Ken from Chicago at September 25, 2006 08:26 AM

Horizontal velocity has an affect on vertical velocity only in so much as the Earth is curved and a truly straight line horizontal movement eventually leads AWAY from the Earth's surface due to its curvature. If the "horizontal" flight was a CURVED flight arc that mirrored Earth then it would be an orbit.

As for the base question

t = time (in seconds), g = -32 ft/sec/sec, then where

v = velocity, v0 = initial velocity (when t = 0)

v = gt + v0

h = gt(t+1)/2 + v0t + h0, thus:

The table really simplies this if you don't want to do the higher order math.

t a v h
0 -32 0 0
1 -32 -32 -32
2 -32 -64 -96
3 -32 -96 -192
4 -32 -128 -320
5 -32 -160 -480
6 -32 -192 -672
7 -32 -224 -896
8 -32 -256 -1152
9 -32 -288 -1440

Where v0 = 0 and h0 = 1000 then

h = gt(t+1)/2 + v0t + h0 = gt(t+1)/2 + 1000
= (gt^2)/2 + gt/2 + 1000
= (-32t^2)/2 + (-32)t/2 + 1000
= -16t^2 - 16t + 1000

When the body hits the ground, h = 0, so

0 = -16t^2 - 16t + 1000
16t^2 + 16t = 1000
t^2 + t = 62.5
t^2 + t + 1/4 - 1/4 = 62.5
t^2 + t/2 + t/2 + 1/4 = 62.5 + 1/4
t(t + 1/2) + (t + 1/2)(1/2) = 62.5 + 0.25
(t + 1/2)(t + 1/2) = 62.75
(t + 1/2)^2 = 125.5/2 = 62.75
t + 1/2 = square root(62.75) = sqrt(62.75)
t = sqrt(62.75) - 0.5
t ~ 8-0.5 ~ 7.5 seconds

-- Ken from Chicago

Posted by: R.J. Carter at September 25, 2006 09:26 AM

Calista and Dolly would fall at the same rate, but Dolly would fall more often given the bounce factor. The real math comes into plotting the declining height of each bounce.

Posted by: David Van Domelen at September 25, 2006 07:09 PM

Falling from 1000 feet wouldn't be enough to kill all that much horizontal velocity.

And a pound of feathers weighs more than a pound of gold. But they use different pounds and different ounces (an ounce of gold weighs more than an ounce of feathers, but there's 16 ounces of feathers in a pound, and only 12 ounces of gold in a pound).

Posted by: Tim Lynch at September 25, 2006 08:28 PM

Okay, all you physics guys out there--would the horizontal velocity change the vertical velocity any?

As was said before I got here, nope -- not unless you're dealing with the curvature of the Earth. (Here's a mind-blower: if you're dealing with the curvature of the Earth, the main reason vertical V gets affected is that the definition of vertical changes as you go. I always have fun asking students that one.)

Now, technically, since air resistance is dependent on your overall velocity, I believe that you might increase the drag somewhat by leaving with a high horizontal V, but my sense is that it won't make a significant amount of difference.

Tim, when you give that problem to your class, do you add that being spread out like a flying squirrel may lead to later problems with two Russian agents and a silly moose?

Alas, no. I've decided in advance that they almost certainly wouldn't get it, and I don't need to be known too strongly as "that weird guy in the basement." (My classroom is in the basement, so the latter part is literal.)

I have a question, is it possible to break terminal velocity, if a person adds some type of thrust to their fall, like Superman flying after Lois after she's been thrown out a window, again.

Absolutely. Terminal V is just defined as the velocity where the upward force of air resistance balances the downward force of your weight. You can certainly be falling faster than that, even without thrust -- it's just that without thrust, the net effect of the two forces will be to gradually slow you back to terminal V. If you're willing to spend the energy to provide a sustained thrust, you can achieve pretty much any reasonable speed you want.

TWL

Posted by: Bill Mulligan at September 25, 2006 09:56 PM

Impact at the first speed (70-80 mph) is survivable with good ground conditions and significant good luck. Impact at the second speed typically requires that friends arrive with mops and squeegees. :-)

So I'm falling out of an airplane over water. It doesn't matter how it happened. OK, I got too insistant on an extra packet of nuts, happy now? Anyway...is my best strategy to spread out like a flying squirrel for the majority of the trip down and then switch to the dart position at the last possible second?

I know that I'd also need to clench my buttocks as much as possible so that my large intestine doesn't shoot out my mouth from the World's Worst Colonic...I'm thinking my butt will be plenty clenched at this point.

Posted by: David Van Domelen at September 25, 2006 10:42 PM

You don't really want to hit water at all...you have to move your mass in water out of the way in a REALLY short time, and that tends to be lethal even if you execute a perfect dive after maxing out your air resistance until the last second.

You want to hit snow, or trees, or better yet, snowy trees on the slope of a ravine full of snow. WWII paratroopers have survived that kind of thing...it's all about making the "slowing down" part take as long as possible.

Posted by: Luigi Novi at September 25, 2006 11:13 PM

Yeah, Tim, I was having trouble seeing the site for the past several days too.

Posted by: Tess at September 26, 2006 06:53 AM

1 Terminal velocity for a human body is right around 120 mph. Hope that helps some.

Posted by: David Hunt at September 26, 2006 11:59 AM

Tim,

Anyone who would tell their parents that they're considering naming their daughter "Mothra" has already made it to weird. You're just hiding it better than some people. The next step is to get you out of the weird closet. If we can get you confined to a garage for a reasonable period of time, I figure that we'll have flubber on the open market within ten years and I'll finally get that flying car they promised me thirty years ago.

And yes, I also experience problem getting onto the sight for several days.

Posted by: Tim Lynch at September 26, 2006 10:08 PM

David,

That only counts as "made it to weird" if I was serious when I told them. If we were just doing it to get a rise out of them (and Lisa participated just as enthusiastically as I did), then that doesn't make us weird, just enjoyably sadistic towards our parents. :-)

TWL

Posted by: Mark L at September 26, 2006 11:18 PM

This is why people think Trekkies are weird, you know :)

Posted by: David Hunt at September 27, 2006 09:24 AM

Details, Tim, Details. If it means I get a flying car, I'm perfectly okay with framing you. ;-)

Posted by: Tim Lynch at September 27, 2006 03:45 PM

If it means I get a flying car, I'm perfectly okay with framing you. ;-)

You do realize that the above statement is permissible in court. :-)

TWL

Posted by: Bill Myers at September 27, 2006 07:54 PM

Okay, this is waaaayyyy off topic but too good not to share.

My uncle fought in the Vietnam War. He didn't want to scare my grandparents, however, so he told them he was going to be stationed in Korea.

After he got back from Vietnam, he decided to marry my aunt. He brought her to meet my grandparents for the first time, so he could announce their engagement.

Upon hearing the announcement, my grandfather looked at my aunt with dead seriousness and said, "I don't think he can marry you unless he divorces his Korean wife."

Like I said, this was the first time my aunt had met my grandfather! My uncle had to spend some time assuring her that my grandfather was a bit of a comedian.

Tim, I think with this story I've got you beat. :)

Posted by: Bill Mulligan at September 27, 2006 09:05 PM

You know, I don't see what's so weird about naming your kid Mothra. I mean, it WAS a girl. It isn't like you named her Megalon or King Caesar.

I wanted to name the CAT Biollante and got overruled so you can see how far MY opinion goes...

On the other hand, I DO get away with calling my beautiful daughter Amanda "Manda". Booyah! And nobody's the wiser!

Posted by: Tim Lynch at September 27, 2006 09:07 PM

That's a good story -- I hope I get the same chance to weird out whoever my daughter brings home.

Straying even further off topic ... I don't think I'll be giving my parents quite the hard time that I did with the "Mothra" thing for a while. My mother was just diagnosed with esophageal cancer earlier today, and just told us the news a couple of hours ago, so I'm in a very weird emotional place right at the moment. Anybody 'round these parts got good stories (and by "good", I mean ones with very cheerful endings) they can share? I could certainly use 'em...

TWL

Posted by: Bill Mulligan at September 27, 2006 11:00 PM

Oh, I'm so sorry to hear that, Tim.

Look, there's no denying that it's a bad kind of cancer. I've experienced it in my own family. My former father in law lived with us for a time while undergoing treatement for it.

So much depends on factors you probably don't know and can't control. That's for the doctors to deal with. What you can and I have no doubt will do is to do anything you can to keep her spirits up and treat the symptoms of th edisease that can cause someone to give up (I don't think that people should have to be dying to get the kind of attention they do in hospices and there is evidence that this kind of palliative care yields big benefits).

But please, please hear me on this--do not let yourself and your own health go to hell while you are helping your mom. I've seen too many people end up in bad shape doing this and nobody is helped by it. It is never selfish to make sure you have the strength to help others but in this situation you see folks feeling guilty for taking care of themselves. Stay strong.

I wish there was something concrete I could do to help. You're a good guy and an intelligent writer and I have no doubt that you are a terrific teacher. I doubt there's a person on this board who isn't hoping this will turn out all right.

Posted by: Megan at September 28, 2006 06:29 AM

Tim, I'm terribly sorry to hear about your Mum. Sending positive thoughts your way.

Megan

Posted by: Sean Scullion at September 28, 2006 09:39 AM

Hey, what's wrong with naming your daughter Megalon? Or Megatron, for that matter? Just call her Meg!

I got a story for you, Tim. WAAAAY back when, first time my sister was pregnant, I drove my mom over to my sister's doctor so we could see the sonogram. The doctor's moving the sensor over Sheil's belly, then says, "You know, I think I see two heads here." Sheil looked absolutely horrified until my mom leaned over and said, "Twins. Not one baby with two heads."

I'm thinking about you and your family, Tim. I know what it's like. Bill's right, though, take care of yourself, too.

Posted by: Tim Lynch at September 28, 2006 12:53 PM

Thanks to all for the well-wishes. We don't really know the status yet (staging and all that is yet to be finished), but the CAT scan showed no evidence of metastasis, which is high on the list of Good Things.

With luck, we'll find out it's at an early stage and it'll respond well to treatment. If so, that's a whole different type of concern than if it's at a more advanced stage. (She's otherwise extremely healthy, which we hope can only be a benefit.) If she's going in for surgery, odds are she'll come to New York to do it, which means she'll be close enough that both my brother and I can drive in to help whenever she needs us. (The few people I've told at school have assured me that the school will do everything it can in terms of logistics to make this easy, too.)

I'm determined not to panic about this until we get the biopsy results back next week. At that point, we'll see.

Again, thanks very much. Now I need to plan for tonight -- it's Back To School Night and I should probably be at least semi-focused...

TWL

Posted by: Bill Myers at September 28, 2006 01:08 PM

Tim, I'm sorry to hear that your mother is ill. I devoutly hope the cancer is indeed at an early stage and is treatable.

For what it's worth, she obviously has an intelligent and good-hearted son in you. Your love and support will undoubtedly make a real difference.

As Bill Mulligan said, please also be sure to also draw on the love and support of those around you to help you through this trying time.

Posted by: Alan Coil at September 28, 2006 06:20 PM

Tess posted: "Terminal velocity for a human body is right around 120 mph."

So how do those NASCAR drivers survive when going over 200 mph?

Posted by: Robert Fuller at September 28, 2006 06:43 PM

Um... was that a joke?

Posted by: Bill Mulligan at September 28, 2006 07:30 PM

(She's otherwise extremely healthy, which we hope can only be a benefit.)

Oh absolutely. It can make all the difference.

One of the problems when people are getting chemo is keeping their weight up. This could be a good time to take up French cooking. Or Soul Food. (My former father-in-law taught me the absolutely best way to cook spinach: fry up a buttload of bacon and then throw the washed spinach leaves onto the bacon grease. Cover the pot before the steam escapes and let the grease and steam cook the spinach. Awesome. yes, it's turning a healthy vegetable into a highly fattening side dish but that was the idea.).

Posted by: Jerry C at September 28, 2006 09:39 PM

Tim, fingers crossed here. Good luck.

Posted by: Tim Lynch at September 28, 2006 10:42 PM

One of the problems when people are getting chemo is keeping their weight up.

Assuming the biopsy results are promising, the treatment actually wouldn't be chemo, at least initially -- it'd be surgery. I'll keep it in mind in case it's necessary, though -- the spinach plan sounds great anyway. :-)

Jerry, thanks much.

TWL

Posted by: The StarWolf at September 29, 2006 09:23 AM

Tim - True story. My late father was misdiagnosed with some sort of tonsolitis and operated on on that basis. A while later, the problem was shown to have been lymphatic cancer and, by then, it was deemed inoperable and terminal. He had a few weeks at best.

He refused to accept the diagnosis and signed up for - then radical - experimental treatment. Eventually he was able to get surgery done after all. It was very hard on him, but he beat it and went on to live another fifteen years.

You just never know. Good luck!

Posted by: Craig J. Ries at September 29, 2006 01:03 PM

Sorry to hear about your mom, Tim. This sounds beatable, so let's hope that's the case.

It's been a bit of a bummer week for me as well.

My late grandmother's cousin's wife (yeah, that's a mouthful), Carol, just passed away over the weekend from lung cancer. While Bob is a distant relation, he's the closest living relation of my grandmother that my dad has left.

So losing Carol is difficult for us, and I'm still frustrated that I couldn't find a way to make it to the funeral yesterday.

Then, while discussing this with my mom, I found out her grandfather has Alzheimer's. So, yeah, bummer week.

Posted by: Bill Myers at September 29, 2006 04:51 PM

Craig, I am sorry to hear about the death in your family, and equally sorry to hear that your great-grandfather is suffering from Alzheimer's. A "bummer week" sounds like a mild way of putting it.

When my grandfather died this summer, each of his seven children wrote one page recounting their favorite memories of him. They did the same thing when my grandmother died last year. It was very comforting. When I find myself feeling sad about losing them, I am able to draw on the decades of wonderful memories they left for me.

I hope your family will find an equal amount of solace in their memories of Carol.

My grandfather had begun suffering from senility (I'm not sure if it was, strictly speaking, Alzheimer's or not) in the months leading up to his death. I think the toughest part was watching this proud rock of a man crumbling, losing his independence, his courage giving way to fear. But I choose to remember him as the proud, strong man he was.

My thoughts are with you and your family, Craig.

Posted by: Craig J. Ries at September 29, 2006 06:08 PM

A "bummer week" sounds like a mild way of putting it.

Yeah, I suppose it is, but it could be worse: I was scanning the obituaries of the newspaper for the area where I went to high school. In the last week, two of the guys I graduated with lost their fathers after long bouts with illness.

I only graduated in 1999 in a class of 96 students, so to see this happen to guys that I knew but wasn't good friends with does tend to put things in perspective against your own situation.

In the end, it's hard to say exactly how these events in my family have really affected me. It certainly isn't to the degree that I'm sure Tim has been affected (and, in a worse case scenario, will be affected) by his news, or these guys I went to school with, but family is family... unless you really hate your family, which I don't. :)

And since the subject of treatments was brought up: Carol had something in the range of 30 chemo treatments for her lung cancer, one a day, five days a week. She was 74, and already of declining health in recent years, so I cannot imagine what she went through.

Hopefully it doesn't come to that for your mom, Tim.

Posted by: Bill Mulligan at September 29, 2006 06:45 PM

Sorry to hear about that, Craig.

Chemo is especially tough on older people. It HAS gotten somewhat better than it once was. A fellow teacher of mine has been fighting advanced breast cancer for some time and the main problem seems to have been fatigue, not pain or nausea.

That said, it's obscene that there is still any question over the use of medical marijuana (or medical freaking heroin as far as I'm concerened). And word of advice to anyone who has a relative in the hospital--fight like crazy to make sure they get all the pain medication they need. It's unbelievably stupid that people in this country have to endure one iota of pain more than necessary. My father in law was given way too little and only the fact that my ex-wife was an actual doctor at the same hospital got them to give him more. I can only imagine how far a regular person would have gotten. Raise a stink, pretend to have relatives at 60 Minutes, do whatever it takes.

Posted by: Craig J. Ries at September 29, 2006 07:00 PM

Chemo is especially tough on older people.

I'm always amazed at how different people react to different treatments, because it just goes to show how hard it is to treat the human body.

We have an elderly woman who lives in our apartment building who, in the last year, found out she had cancer (I forget the type). She has gone through chemo, and now the cancer is in remission. She's a little worse for wear, but seems to be doing well; she's always in good spirits, regardless.

Yet, when I was still in high school, a best friend's mother had recurring cancer. It would come back, she would go through chemo, it would go into remission; it was like this for several years. She finally succumbed to it about a year after we graduated, but I was remember that, after she had a chemo treatment, she always seemed to have *more* energy for a day or so. She was an incredible person as well.

Posted by: Tim Lynch at October 2, 2006 06:00 PM

My condolences on all of your bad news, Craig. Must be the season for it or something. (And I certainly know how you feel about your great-grandfather's news -- my grandmother passed away from Alzheimer's about ten years ago. Nobody had much of a sense of how bad it was for the first few years, but once my grandfather passed away it became very obvious very fast.)

Mom was here visiting for the weekend, which was nice for everyone, I think. She and I talked for a long time -- if nothing else, she knows now that she's got a place to stay if she does come to NY for treatment. (I hope she already knew that, of course.) We're still waiting for news about what stage it is -- we'll probably find that out later this week. We've all got fingers crossed -- Stage I is VeryVeryGood when it comes to survival rates, and Stage III or IV is VeryVeryVeryBad. II's somewhere in the middle. There are a great many crossed fingers these days.

School has been great about this -- all the higher-ups are saying "once you know what you need logistically, let us know and we'll make sure it happens." If I'm going to be gone for long stretches, I'll have to tell the students at some point ... but not yet.

Meanwhile, I can handle the mundane stuff -- off to finish making dinner for when the rest of the household comes home. :-)

TWL

Posted by: Bill Myers at October 2, 2006 06:08 PM

Tim, I will also keep my fingers crossed for you and your mother.